Positive real numbers x and y satisfy the equations x^2 + y^2 = 1 and x^4 + y^4 = 5/8. Find xy.
answer: sqrt(3)
Hello Guest,
there are 5 solutions, but one of them have positive real numbers.
\((x,y)=(\frac{1}{2},\frac{\sqrt{3}}{2})\) \(\mbox {wolframalpha}\)
\(\frac{1}{2}*\frac{\sqrt{3}}{2}= \mbox { } \approx {0.433}\) .
Straight
You can do it like this:
