+330 Assume that f(3) = 4. Name a point that must be on the graph of y= (5 + f(2x/3))/11$.
+1926 We know that f(3) = 4, so we want the inside of f(2x/3) to equal 3. We notice that when we have x=9/2, then we have \(y=\frac{5+f(3)}{11} = \frac{5+4}{11}\).
This is easily solvable, so we get y=9/11.
This means that the point (9/2, 9/11) has to be on the line.
Thanks!
