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Assume that f(3) = 4. Name a point that must be on the graph of y= (5 + f(2x/3))/11$.

 May 3, 2024
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We know that f(3) = 4, so we want the inside of f(2x/3) to equal 3. We notice that when we have x=9/2, then we have \(y=\frac{5+f(3)}{11} = \frac{5+4}{11}\)

 

This is easily solvable, so we get y=9/11. 

 

This means that the point (9/2, 9/11) has to be on the line. 

 

Thanks!

 May 3, 2024
edited by NotThatSmart  May 3, 2024

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