Fill in the blanks with numbers to make a true equation.
3x^2 + 12x - 4 - 2x^2 + 6x + 7 = ___ (x + ___ )^2 + ___
I'm not sure if you can use 1 in the first blank but here's what I got
3x2+12x−4−2x2+6x+7=x2+18x+3=(x+9)2−78=1(x+9)2+(−78)
3x^2 + 12x - 4 - 2x^2 + 6x + 7 = ___ (x + ___ )^2 + ___
x^2+18x+3= ___ (x + ___ )^2 + 3
x^2+18x=___(x+___)+ ____
(x+9(cuz 9*2=18)---> (x+9)^2= x^2+18x+81
so answer is 1(x+9)^2+84
I'm not sure if you can use 1 in the first blank but here's what I got
3x2+12x−4−2x2+6x+7=x2+18x+3=(x+9)2−78=1(x+9)2+(−78)