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Algebra

0

24

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+965

Find the coefficient of u^2*v^9 in (2u - 3*v^3)*5*(3u^3 - 2v^5)^3.

magenta Jun 24, 2024

3⁺² Answers

+1950

+1

I basically expanded everything out.

$120v^{18}-540u^{3}v^{13}-80uv^{15}+810u^{6}v^{8}+360u^{4}v^{10}-405u^{9}v^{3}-540u^{7}v^{5}+270u^{10}$

hmmm...there is no u^2v^9 term.

So the coefficient is just 0.

So 0 is our answer.

Thanks! :)

NotThatSmart Jun 24, 2024

+84

0

XD just expanding is definentaly(100% misspelled) a way to do it

shmewy Jun 24, 2024

edited by shmewy Jun 24, 2024

+1950

+1

I know there are smarter ways to do it...but I'm not smart...as my name suggests

We could simply just take a look at the factors.

$(2u - 3*v^3)*5*(3u^3 - 2v^5)^3$ never has a term for v^9, so it's impossible.

We can easily tell, but ummm...yeah....

XD :)

~NTS

NotThatSmart Jun 24, 2024

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