+193 What is the relative maximum and minimum of the function?
F (x) = 2x^3 + x 2 – 11x
The relative maximum is at (–1.53, 8.3) and the relative minimum is at (1.2, –12.01).
The relative maximum is at (–1.53, 12.01) and the relative minimum is at (1.2, –8.3).
The relative maximum is at (–1.2, 8.3) and the relative minimum is at (1.53, –12.01).
The relative maximum is at (–1.2, 12.01) and the relative minimum is at (1.53, –8.3).
+129852 F(x) = 2x^3 + x^2 - 11x
Don't know if you have had Calculus.....but we can find these quickly
Take the derivative and set to 0
F' (x) = 6x^2 + 2x - 11 = 0
The solutions to this are x = -1.53 and x = 1.2
The second derivative is
12x + 2
Plugging the first x value into this results in a negative.....so we have a relative max at x = -1.53
And plugging the second value into this results in a positive.....so we have a relative min at x =1.2
Putting (-1.53) into the original function results in y = 12.01
Putiing (1.2) into the original function results in y = -8.3
So.....the rel max is (-1.53, 12.01) and a rel min at (1.2, -8.3)
So....the second answer is correct
