What is the relative maximum and minimum of the function?

F (x) = 2x^3 + x 2 – 11x

The relative maximum is at (–1.53, 8.3) and the relative minimum is at (1.2, –12.01).

The relative maximum is at (–1.53, 12.01) and the relative minimum is at (1.2, –8.3).

The relative maximum is at (–1.2, 8.3) and the relative minimum is at (1.53, –12.01).

The relative maximum is at (–1.2, 12.01) and the relative minimum is at (1.53, –8.3).

Littlegirlblue Jan 29, 2019

#1**+2 **

F(x) = 2x^3 + x^2 - 11x

Don't know if you have had Calculus.....but we can find these quickly

Take the derivative and set to 0

F' (x) = 6x^2 + 2x - 11 = 0

The solutions to this are x = -1.53 and x = 1.2

The second derivative is

12x + 2

Plugging the first x value into this results in a negative.....so we have a relative max at x = -1.53

And plugging the second value into this results in a positive.....so we have a relative min at x =1.2

Putting (-1.53) into the original function results in y = 12.01

Putiing (1.2) into the original function results in y = -8.3

So.....the rel max is (-1.53, 12.01) and a rel min at (1.2, -8.3)

So....the second answer is correct

CPhill Jan 29, 2019