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What is the relative maximum and minimum of the function?

F (x) = 2x^3 + x 2 – 11x

 

 

The relative maximum is at (–1.53, 8.3) and the relative minimum is at (1.2, –12.01).

 

The relative maximum is at (–1.53, 12.01) and the relative minimum is at (1.2, –8.3).

 

The relative maximum is at (–1.2, 8.3) and the relative minimum is at (1.53, –12.01).

 

The relative maximum is at (–1.2, 12.01) and the relative minimum is at (1.53, –8.3).

 Jan 29, 2019
 #1
avatar+102372 
+2

F(x)  = 2x^3  + x^2 - 11x

 

Don't know if you have had Calculus.....but we can find these quickly 

 

Take the derivative and set to 0

 

F' (x)  = 6x^2 + 2x - 11  = 0

 

The solutions to this are x = -1.53   and x = 1.2

 

The second derivative is

 

12x + 2

 

Plugging   the first x value into this results in a negative.....so we have a relative max at x = -1.53

And plugging the second value into this results in a positive.....so we have a relative min at x =1.2

 

Putting (-1.53) into the original function results in y = 12.01

Putiing (1.2) into the original function results in y = -8.3

 

So.....the rel max is (-1.53, 12.01)   and a rel min at (1.2, -8.3)

 

So....the second answer is correct

 

 

cool cool cool

 Jan 29, 2019

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