+729 Let x, y, and z be nonzero real numbers. Find all possible values of
\frac{x}{x} + \frac{y}{y} + \frac{z}{z} + \frac{xyz}{xyz}
+1365 Well, let's first note something.
We have \(\frac{x}{x} = 1\) as long as x is not 0.
We have \(\frac{y}{y} = 1\) as long as y is not 0.
We have \( \frac{z}{z} =1\) as long as z is not 0.
We finally have \(\frac{xyz}{xyz} = 1\) as long as x,y,z are not 0.
So, we have \(1+1+1+1 = 4\) as long as \(x,y,z \neq 0\)
So there is only one possible value.
Thanks! :)
