Find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 34.
(2n - 1) + 2 ( 2n + 1) + 3(2n + 3) = 34
2n - 1 + 4n + 2 + 6n + 9 = 34
12n + 10 = 34
12n = 34 -10
12n = 24
n = 24 / 12 = 2
The integers are
2(2) - 1 , 2(2) + 1 , 2(2) + 3
3 , 5 , 7
