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Find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 34.

 Jun 13, 2022
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(2n - 1)  + 2 ( 2n + 1) + 3(2n + 3)  =  34

 

2n - 1  + 4n + 2 + 6n + 9  =  34

 

12n + 10   =  34

 

12n  =  34 -10

 

12n =  24

 

n = 24 / 12  =  2

 

The integers  are

 

2(2) - 1   ,   2(2) + 1  ,  2(2) +  3

 

3  ,  5   ,   7

 

 

 

cool cool cool

 Jun 13, 2022

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