+12 Write a quadratic equation that has the projectile being launched from 6 feet off the ground
+150 The general quadratic equation for a projectile's free fall is
\(p(t) = -at^2 + v_0t + h,\)
where \(a\) represents acceleration due to gravity, \(v_0\) is the initial (launch) velocity of the projectile, and \(h\) is our starting height.
In terms of feet, the acceleration of a projectile due to gravity (on Earth) comes out to \(32.17 \frac{\text{ft}}{\text{s}^2}\). I'll assume from your statement that there's no initial velocity present. Then, with a starting height of 6 feet, our quadratic equation will take the form
\(p(t) = -32.17t^2 +6.\)
