Write a quadratic equation that has the projectile being launched from 6 feet off the ground

SBAHarper May 2, 2022

#1**+2 **

The general quadratic equation for a projectile's free fall is

\(p(t) = -at^2 + v_0t + h,\)

where \(a\) represents acceleration due to gravity, \(v_0\) is the initial (launch) velocity of the projectile, and \(h\) is our starting height.

In terms of feet, the acceleration of a projectile due to gravity (on Earth) comes out to \(32.17 \frac{\text{ft}}{\text{s}^2}\). I'll assume from your statement that there's no initial velocity present. Then, with a starting height of 6 feet, our quadratic equation will take the form

\(p(t) = -32.17t^2 +6.\)

Anthrax May 2, 2022