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Let x and y be nonnegative real numbers. If x^2 + 3y^2 = 18, then find the maximum value of x + y.

 May 27, 2024
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This might seem like a weird way to do it, but like others, I would reccommend the Cauchy-Schwarz inequality.

 

Essentially, what this inequality states is that where a and b are real numbers, we can write the inequality (a21+a22++a2n)(b21+b22++b2n)(a1b1+a1b2++anbn)2

 

We could apply this to this problem!

We have (x2+3y2)(1+13)(x+3(13)y)2

 

1843(x+y)2

x+y24

 

Clearly, from this equation, we find that the maximum value is 24

 

We could probably brute force this problem, but this trick is defintely easier!

 

Thanks! :)

 May 27, 2024

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