Algebra

First, let's set up a quadratic equation for x. Combining some like terms, we get

$-8x^2-kx+47=0$

Now, in order for the problem to have no real solutions, the descriminant must be less than 0. 

Thus, let's set up the descriminant to find k. 

We get that

$k^2+1504<0$

Isolating k, we get

$k^2<-1504$

However, note that k^2 cannot be negative, meaning that k^2 cannot possibly be smaller than -1504. 

Therefore, it is impossible for the equation to have no real solutions. 

Thanks! :)