Find all the solutions to
\frac{x+4}{x+5} = \frac{x-3}{2} + \frac{x + 7}{5}
First, we want to get rid of the nasty fractions.
Let's do this by multiplying both sides by the LCM of the denominators.
By doing this, we have
10(x+4)=5(x−3)(x+5)+2(x+7)(x+5)
Distributing every number in and moving all terms to one side, we have
7x2+24x−45=0
Using the quadratic equation and finding what x is, we have
x=3√51−127x=−3√51−127
Thanks! :)