The expression 3y^2-y-24+10 can be written as (3y + a)(y + b), where a and b are integers. What is a-b?
+9674 Note that \(3y^2 - y - 24 + 10 = 3y^2 - y - 14\).
Then, note that -y = 6y - 7y, so we have:
\(\begin{array}{cl} & 3y^2 - y - 14\\ =& 3y^2 + 6y - 7y - 14\\ =& 3y(y + 2) - 7(y + 2) \end{array}\)
Now you can take out the common factor (y + 2) and compare with what the question gave you. Can you proceed from here?
