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Solve for the variable x in terms of y and z, assuming y \neq \frac{1}{2}:
xy + x = \frac{3x + 2y + z + y + 2z}{3}

 May 9, 2024
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xy+x=3x+2y+z+y+2z3xy+x=x+2y3+z3+y3+2z3xy+x=x+y+zxy=y+zx=y+zy

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 May 9, 2024

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