To make the equation clear, it looks like this: \({y\over3}+1={y+3\over y}+7\).
Then multiply every term by '3y'.
It should now look like this:\(y^2 + 3y = 3y + 9 + 21y\).
Combining like terms and moving the equation to one side, we get: \(y^2 - 21y - 9 = 0\).
Then you can use the quadratic formula \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) where a is the coefficient of x^2. b is the coefficient of x, and c is the constant.
Plugging in the values, we have:
\(y = {21 + 3\sqrt{53}\over2}\)
\(y = {21-3\sqrt{53}\over2}\)
Those are the two possible values of y :)