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Will and Grace are canoeing on a lake.  Will rows at $50$ meters per minute and Grace rows at $30$ meters per minute. Will starts rowing at $2$ p.m. from the west end of the lake, and Grace starts rowing from the east end of the lake at $2{:}45$ p.m. If they always row directly towards each other, and the lake is $2800$ meters across from the west side of the lake to the east side, at what time will the two meet?

 Sep 24, 2024
 #1
avatar+37146 
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Will has covered 45 minutes worth of lake distance  

       45 min  * 50 m/min = 2250 m meters before Grace starts ....so there is only   2800 - 2250 = 550 meters to cover before they meet 

               their closing rate is (50 + 30 )  = 80 m/min 

                              distance / rate = time 

                                         550 m / 80 m/min = 6 7/8 minutes they will meet after Gracie starts 

                  which would be   2:45 + 6 7/8  = 2:51  and 7/8 = 2:51 and 52.5 seconds  (almost  2:52 pm) 

 Sep 24, 2024

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