Will and Grace are canoeing on a lake. Will rows at $50$ meters per minute and Grace rows at $30$ meters per minute. Will starts rowing at $2$ p.m. from the west end of the lake, and Grace starts rowing from the east end of the lake at $2{:}45$ p.m. If they always row directly towards each other, and the lake is $2800$ meters across from the west side of the lake to the east side, at what time will the two meet?

gnistory Sep 24, 2024

#1**+1 **

Will has covered 45 minutes worth of lake distance

45 min * 50 m/min = 2250 m meters before Grace starts ....so there is only 2800 - 2250 = 550 meters to cover before they meet

their closing rate is (50 + 30 ) = 80 m/min

distance / rate = time

550 m / 80 m/min = 6 7/8 minutes they will meet after Gracie starts

which would be 2:45 + 6 7/8 = 2:51 and 7/8 = 2:51 and 52.5 seconds (almost 2:52 pm)

ElectricPavlov Sep 24, 2024