How many liters of pure water should be mixed with a 30L solution of 60% acid to produce a mixture that is 70% water?

Guest Oct 1, 2020

#1**+1 **

How many liters of pure water should be mixed with a 30L solution of 60% acid to produce a mixture that is 70% water? How many liters of pure water should be mixed with a 30L solution of 60% acid to produce a mixture that is 70% water?

**Hello Guest!**

\(x+30l\cdot (100-60)\%=(30l+x)\cdot 70\%\)

\(x+30l\cdot 0.4=30l\cdot 0.7+0.7x\\ x-0.7x=30l\cdot (0.7-0.4)\\ 0.3x=0.3\cdot 30l \)

\(x=30l\)

30 liters of pure water should be mixed with a 30L solution of 60% acid to produce a mixture that is 70% water?

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asinus Oct 1, 2020