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# Algebra

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1.

What is the solution to the inequality?

4(2x+5)−2x≥10

Apr 5, 2021

#1
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$4(2x+5)-2x=8x+20-2x=6x+20$.

Now the inequality is:

$6x+20>=10$

$6x>=-10$

$x>=-6$

Or, in interval notation: $\boxed{[-6, \infty)}$

Apr 5, 2021
#2
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Thank you but the correct answer is x≥-5/3.

I did the same thing you did, so i thought that was the correct answer as well. Apparently not. Thanks a lot though. c:

Guest Apr 5, 2021
#3
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Oh my god, thank you so much, I just realized where I went wrong. I had a brain freeze, on the last step, where I divide by 6, you get $x>=\frac{-10}{6}=\frac{-5}{3}$, not $x>=-6$. I'm really sorry.

RiemannIntegralzzz  Apr 5, 2021
#4
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Its okay!! I did the same thing you did thinking it was correct. Its not a problem! I appreciate your help!

Guest Apr 5, 2021
#5
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Hey there, Guest!

$$4(2x+5)−2x≥10$$

Step 1: Simplify both sides of the inequality.

$$6x+20≥10$$

Step 2: Subtract 20 from both sides.

$$6x+20−20≥10−20$$

$$6x≥−10$$

Step 3: Divide both sides by 6.

$$\frac{6x}{6}$$$$≥$$$$\frac{-10}{6}$$

Therefore, your answer is $$x≥ \frac{-5}{3}$$.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Apr 5, 2021