1.

What is the solution to the inequality?

4(2x+5)−2x≥10

Enter your answer in the box.

Guest Apr 5, 2021

#1**0 **

$4(2x+5)-2x=8x+20-2x=6x+20$.

Now the inequality is:

$6x+20>=10$

$6x>=-10$

$x>=-6$

Or, in interval notation: $\boxed{[-6, \infty)}$

RiemannIntegralzzz Apr 5, 2021

#2**0 **

Thank you but the correct answer is x≥-5/3.

I did the same thing you did, so i thought that was the correct answer as well. Apparently not. Thanks a lot though. c:

Guest Apr 5, 2021

#3**0 **

Oh my god, thank you so much, I just realized where I went wrong. I had a brain freeze, on the last step, where I divide by 6, you get $x>=\frac{-10}{6}=\frac{-5}{3}$, not $x>=-6$. I'm really sorry.

RiemannIntegralzzz
Apr 5, 2021

#5**+1 **

Hey there, Guest!

Let's solve your inequality step-by-step.

\(4(2x+5)−2x≥10\)

Step 1: Simplify both sides of the inequality.

\(6x+20≥10\)

Step 2: Subtract 20 from both sides.

\(6x+20−20≥10−20\)

\(6x≥−10\)

Step 3: Divide both sides by 6.

\(\frac{6x}{6}\)\(≥\)\(\frac{-10}{6}\)

Therefore, your answer is \(x≥ \frac{-5}{3}\).

Hope this helped! :)

( ﾟдﾟ)つ Bye

TaliaArticula Apr 5, 2021