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1.

What is the solution to the inequality?

4(2x+5)−2x≥10

 

Enter your answer in the box.

 Apr 5, 2021
 #1
avatar+484 
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$4(2x+5)-2x=8x+20-2x=6x+20$.

 

Now the inequality is:

 

$6x+20>=10$

$6x>=-10$

$x>=-6$

 

Or, in interval notation: $\boxed{[-6, \infty)}$

 Apr 5, 2021
 #2
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Thank you but the correct answer is x≥-5/3. 

I did the same thing you did, so i thought that was the correct answer as well. Apparently not. Thanks a lot though. c: 

Guest Apr 5, 2021
 #3
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Oh my god, thank you so much, I just realized where I went wrong. I had a brain freeze, on the last step, where I divide by 6, you get $x>=\frac{-10}{6}=\frac{-5}{3}$, not $x>=-6$. I'm really sorry.

RiemannIntegralzzz  Apr 5, 2021
 #4
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Its okay!! I did the same thing you did thinking it was correct. Its not a problem! I appreciate your help!

Guest Apr 5, 2021
 #5
avatar+320 
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Hey there, Guest!

 

Let's solve your inequality step-by-step.

\(4(2x+5)−2x≥10\)

 

Step 1: Simplify both sides of the inequality.

\(6x+20≥10\)

 

Step 2: Subtract 20 from both sides.

\(6x+20−20≥10−20\)

\(6x≥−10\)

 

Step 3: Divide both sides by 6.

\(\frac{6x}{6}\)\(≥\)\(\frac{-10}{6}\)

 

Therefore, your answer is \(x≥ \frac{-5}{3}\).

 

Hope this helped! :)

( ゚д゚)つ Bye

 Apr 5, 2021

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