Algebra

First, let's combine all like terms. We get

\(y=-5x^2-6x+10\)

 

Now, the equation for the x value of the vertex is

\(x=\frac{-b}{2a}\) for quadratics in the form of \(ax^2+bx+c\)

 

Thus, we have \(x=\frac{-(-6)}{2(-5)} =- \frac{6}{10}\)

 

Plugging in x into the equation for y, we have 

\(y=\frac{59}{5}\)

 

Thus the vertex is \(\left(-\frac{3}{5},\:\frac{59}{5}\right)\)

 

So our answer is \(\left(-\frac{3}{5},\:\frac{59}{5}\right)\)

 

Thanks! :)