+1323 Find the vertex of the graph of the equation y = -2x^2 + 8x - 15 - 3x^2 - 14x + 25.
+1806 First, let's combine all like terms. We get
\(y=-5x^2-6x+10\)
Now, the equation for the x value of the vertex is
\(x=\frac{-b}{2a}\) for quadratics in the form of \(ax^2+bx+c\)
Thus, we have \(x=\frac{-(-6)}{2(-5)} =- \frac{6}{10}\)
Plugging in x into the equation for y, we have
\(y=\frac{59}{5}\)
Thus the vertex is \(\left(-\frac{3}{5},\:\frac{59}{5}\right)\)
So our answer is \(\left(-\frac{3}{5},\:\frac{59}{5}\right)\)
Thanks! :)
