The positive difference between two consecutive odd perfect squares is \(328\). Compute the larger of the two squares.
+2666 We can write this as an equation: \(x^2+328=(x+2)^2\)
Simplifying, we get: \(x^2+328=x^2+4x+4\)
Solving, we find: \(x= 81\)
Thus, the larger square is \(81+2=\color{brown}\boxed{83}\)
