+0  
 
0
41
5
avatar

The sum of three numbers a, b, and c is 99. If we increase a by 5, decrease b by 5 and multiply c by 5, the three resulting numbers are equal. What is the value of b?

 Aug 26, 2021
 #1
avatar
0

The value of b is 44/7.

 Aug 26, 2021
 #2
avatar
0

a + b + c ==99.......................(1)

 

[a+5] = [a-5] = [c*5].............(2), solve for a, b, c

 

Use substitution to get:

a==40,  b==50,   c==9

 Aug 26, 2021
 #3
avatar
0

a + b + c = 99

a + 5 = b - 5 ===> a = b + 10

b - 5 = 5c  ===> c = \({b - 5} \over 5\)

 

so b + 10 + b + \({b - 5} \over 5\) = 99

so 5b + 50 + 5b + b - 5 = 495

so 11b - 45 = 495

so 11b = 540

so b = \(540 \over 11\)

 Aug 26, 2021
 #4
avatar
0

wait, made a mistake, a = b - 10

so 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

5b - 50 + 5b + b - 5 = 495

11b - 55 = 495

11b = 550

so b = 50

Guest Aug 26, 2021
 #5
avatar
0

i agree with second answer

Guest Aug 26, 2021

11 Online Users

avatar