The sum of three numbers a, b, and c is 99. If we increase a by 5, decrease b by 5 and multiply c by 5, the three resulting numbers are equal. What is the value of b?
a + b + c ==99.......................(1)
[a+5] = [a-5] = [c*5].............(2), solve for a, b, c
Use substitution to get:
a==40, b==50, c==9
