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# algebra

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Find all values of x such that x^2 - 5x + 6 = 0. If you find more than one value, then list your solutions in increasing order, separated by commas.

Dec 29, 2020

#1
+1

x2 -5x + 6 = 0        Factor

(x-3)(x-2) = 0        at least one of these factors must = 0

x-3 = 0

x = 3         or   x-2 = 0

x = 2

You can also use the Quadratic Formula to solve this

a =1      b = -5      c = 6

$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$

$$x = {-(-5) \pm \sqrt{(-5)^2-4(1)(6)} \over 2(1)}$$

Dec 29, 2020

#1
+1

x2 -5x + 6 = 0        Factor

(x-3)(x-2) = 0        at least one of these factors must = 0

x-3 = 0

x = 3         or   x-2 = 0

x = 2

You can also use the Quadratic Formula to solve this

a =1      b = -5      c = 6

$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$

$$x = {-(-5) \pm \sqrt{(-5)^2-4(1)(6)} \over 2(1)}$$

Guest Dec 29, 2020