+579 Hello,
\(x^2-y^2=51+xy\)
\(x^2-y^2-xy=51\)
\(x^2-yx-y^2-51=0\)
Solve with the quadratic formula:
\(x_{1,\:2}=\frac{-\left(-y\right)\pm \sqrt{\left(-y\right)^2-4\cdot \:1\cdot \left(-y^2-51\right)}}{2\cdot \:1}\)
\(x_{1,\:2}=\frac{-\left(-y\right)\pm \sqrt{5y^2+204}}{2\cdot \:1}\).
I think you got \(y\)...
Let me know if you need help becoz this might get very messy.Good luck
