+129840 Well....it could be lots of things.....but....let's try this one.........
Let's assume that this is the bottom half of a sideways parabola opening to the right
Let's call the vertex (h,k) = (5 ,6) and we know that point (9, -2) is on the graph.......so........we have this form :
(x - 5) = a(y - 6)^2 now......substitute 9 for x and -2 for y and solve for a......and we have
(9 -5) = a(-2 - 6)^2
4 = a(64) divide both sides by 64
a = 4/64 = 1/16
So........our full equation is
(x - 5) = (1/16)(y - 6)^2 but we only want the bottom part of the graph....so....
Multiply both sides by 16
16(x - 5) = (y - 6)^2 take the pos/neg square roots of both sides
± 4 √ (x - 5) = y - 6
Since we want the bottom part, we will take the negative root
- 4 √ (x - 5) = y - 6 add 6 to both sides
-4 √ (x - 5) + 6 = y and we can write this as :
y = -4 √ (x - 5) + 6
Here's the graph : https://www.desmos.com/calculator/tpovquifna
