+80 Alright, let's break this down by simplifying it.
\((6x+1/3x)^2 \)
\(=(6x+\frac{1}{3x})^2\)
Now we can apply the formula
\((a+b)^2=a^2+2ab+b^2\)
or in this case,
\((6x + \frac{1}{3x})^2 = 6x^2+2(6x)\frac{1}{3x}+\frac{1}{3x}^2\)
which will become:
6x^2 + 4 + 1/3x2, since 2*6x is 12x, and 12x+1/3x is 12x/3x. Divide by 3x and you get the answer, \(\fbox{4}\)
+80 Ah. I constantly forget to pay attention to the details. Thanks for the heads up!
