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Find the constant k such that the quadratic 2x^2 + 3x + 8x - x^2 + 4x + k has a double root.

 Jul 16, 2024
 #1
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First, let's combine all like terms and reaarange so we have the shape of a quadratic formula. 

We get

\(x^2 + 15x + k \)

 

Having a double root means that the descriminant is greater than 0, so we have the equation

\(15^2 - 4 (1)(k) = 0 \\ 225 - 4k = 0 \\ 225 = 4k \\ k = 225 / 4\)

 

thus, The value of k is \(k = 225 / 4 \)

 

Thanks! :)

 Jul 16, 2024
edited by NotThatSmart  Jul 16, 2024

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