John and Jane go rock-climbing together. John climbs a height of (x+5) miles in (x-1) hours and Jane climbs a height of (x+11) miles in (x+2) hours. Is it possible that they were climbing at the same speed? If so, what must have been their speed, in miles per hour? If not, use 0 as your answer.

Guest Sep 6, 2021

#1**+1 **

Srt the RATES equal and solve for 'x'

(x+5) / (x-1) = (x+11)/(x+2) solve for 'x' (if possible ) Start by cross multiplying, simplify then use Quadratic FOrmula

..... Post if you need more help....

Then speed in MPH = (x+5)/(x-1) or (x+11)/(x+2) <===== they should be the same for the Q

ElectricPavlov Sep 6, 2021