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If $x-y=15$ and $xy=4$, what is the value of $x^2+y^2$?

 Dec 28, 2018
 #1
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\((x-y)^2 = (x^2 + y^2) - 2xy\\ x^2 + y^2 = (x-y)^2 + 2xy = \\ 225+8 = 233\)

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 Dec 28, 2018
 #2
avatar+559 
-1

\((x-y)^2=(x^2+y^2)-2xy\)

Substituting our given numbers,

\(15^2=(x^2+y^2)-2(4), 225=(x^2+y^2)-8, x^2+y^2=233\)

 

You are very welcome!

:P

 Dec 28, 2018

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