Find all ordered pairs (x,y) of real numbers such that x + y = 10 and x^2 + y^2 = 62 + 2xy.
For example, to enter the solutions $(2,4)$ and $(-3,9)$, you would enter "(2,4),(-3,9)" (without the quotation marks).
{x+y=10x2+y2=62+2xy(x−y)2=62x−y=±√62
When x - y = √62, (x,y)=(10+√622,10−√622).
Otherwise, (x,y)=(10−√622,10+√622).
These 2 pairs are all the solutions.
+1855 
