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# Algebra

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1.     Suzette ran and biked for a total of 60 mi in 6 h. Her average running speed was 4 mph and her average biking speed was 12 mph.

Let x = total hours Suzette ran.

Let y = total hours Suzette biked.

Use substitution to solve for x and y. Show your work. Check your solution.

(a)   How many hours did Suzette run?

(b)   How many hours did she bike?

Nov 15, 2019

#1
+1

first things first, you need two equations

the two equations are 4x+12y=60 and x+y=6

then you want to simplify like dividing the first equation by 4

so it would be x+3y=15

now you want to subtract the other equation from it to get rid

of x so now it would be 0x+2y=9

then we simplify again so 2y/2=9/2

and it would be y=4.5

now we replace y with 4.5 in one of the equations (I did the second one

but you'll get the same answer if you do the first) so it would be x+4.5=6

than subtract 4.5 from both sides and your done and that leaves you with

1.5 hours runing and 4.5 hours biking

Nov 15, 2019
edited by ChessPlayer  Nov 15, 2019

#1
+1

first things first, you need two equations

the two equations are 4x+12y=60 and x+y=6

then you want to simplify like dividing the first equation by 4

so it would be x+3y=15

now you want to subtract the other equation from it to get rid

of x so now it would be 0x+2y=9

then we simplify again so 2y/2=9/2

and it would be y=4.5

now we replace y with 4.5 in one of the equations (I did the second one

but you'll get the same answer if you do the first) so it would be x+4.5=6

than subtract 4.5 from both sides and your done and that leaves you with

1.5 hours runing and 4.5 hours biking

ChessPlayer Nov 15, 2019
edited by ChessPlayer  Nov 15, 2019