+42 If we combine like terms, we get \(x^2+12x-4\). By Vieta's, the sum of the roots is -12 and the product is -4. If the roots are a and b, then \((a+b)^2=-12^2=144\). If we subtract twice the product, we can find the sum of the squares of the roots. \(144-(-8)=152\).
Feel free to tell me if I did anything wrong! :D
+42 If we combine like terms, we get \(x^2+12x-4\). By Vieta's, the sum of the roots is -12 and the product is -4. If the roots are a and b, then \((a+b)^2=-12^2=144\). If we subtract twice the product, we can find the sum of the squares of the roots. \(144-(-8)=152\).
Feel free to tell me if I did anything wrong! :D
