+1790 First, let's isolate a^3 as much as possible.
We have
\(\frac{1}{64a^3+7}=7\\448a^{3}+49=1\\ 448a^3=-48\\ a^3=-48/448 \)
From this, we get that
\(a=\sqrt[3]{-28/3}\)
This is actually the only real factor for a, so it is our final answer.
Thanks! :)
+1790 First, let's isolate a^3 as much as possible.
We have
\(\frac{1}{64a^3+7}=7\\448a^{3}+49=1\\ 448a^3=-48\\ a^3=-48/448 \)
From this, we get that
\(a=\sqrt[3]{-28/3}\)
This is actually the only real factor for a, so it is our final answer.
Thanks! :)
