There are numbers A and B for which
A/(x - 1) + B/(x + 1) = (8x + 3)/(x^2 - 1)
for every number $x^2 \neq 1$. Find B.
+36916 A/(x - 1) + B/(x + 1) = (8x + 3)/(x^2 - 1) Multiply both sides of the equation by (x^2-1)
A (x+1) + B (x-1) = 8x+3
Ax + A + Bx -B = 8x+3 equat the 'x' parts and the constant parts
A+B = 8 and A-B = 3 <======= two equations two unknowns.....solve for A and B
Add the two equations 2A = 11 so A = 5.5 then B = 2.5
