Lisa leaves a gas station and drives at an average rate of 50 mi/hr. Keisha leaves the gas station one hour later and drives along the same route at an average rate of 60 mi/hr. Let d represent the distance driven in miles and t represent the time since Lisa left the gas station. Which system of equations can be used to find how long after Lisa left the gas stations that she is passed by Keisha?
+934 Lisa has driven 50 miles by the time Keisha leaves. Keisha gains 10 miles on Lisa per hour so it would take Keisha 5 hours to catch up to Lisa.
d=50t
d=60(t+1)
Hope it helps!
+934 Lisa has driven 50 miles by the time Keisha leaves. Keisha gains 10 miles on Lisa per hour so it would take Keisha 5 hours to catch up to Lisa.
d=50t
d=60(t+1)
Hope it helps!
