Determine the unique pair of real numbers (x,y) satisfying (3x^2 + 5)(2y^2 + 8) = 40. Enter your answer as an ordered pair in the format (x,y), where x and y are replaced by appropriate numbers.
Note that 5 and 8 both multiply to 40.
This means that \(3x^2 = 0\) and \(2y^2 = 0 \)
Can you take it from here?