Algebra

First, moving all terms to one side other than the constants, we get

\(x^2+y^2-6x-6y=56\)

Completing the square for both x and y, we get

\(\left(x-3\right)^2+\left(y-3\right)^2=\left(\sqrt{74}\right)^2\)

Thus, the radius is

\(r=\sqrt{74}\)

Using the circle equation, we have

AREA OF CIRCLE = \(\sqrt{75}^2\pi = 74\pi\)

Thus, 74pi is the answer. 

Thanks! :)