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Find all solutions to the equation 6x^2 - 31x + 42 = 0. If you find more than one, then list the values separated by commas. If the solutions are not real, then they should be written in a + bi form.

 Aug 12, 2021

Best Answer 

 #1
avatar+502 
+2

Lets solvie this:

\(6x^2-31x+42=0\)

 

\(\frac{-\left(-31\right)\pm \sqrt{\left(-31\right)^2-4\cdot \:6\cdot \:42}}{2\cdot \:6}\)

 

\(\frac{-\left(-31\right)\pm \sqrt{47}i}{2\cdot \:6}\)

 

separate: \(x_1=\frac{-\left(-31\right)+\sqrt{47}i}{2\cdot \:6},\:x_2=\frac{-\left(-31\right)-\sqrt{47}i}{2\cdot \:6}\)

 

\(x=\frac{31}{12}+\frac{\sqrt{47}}{12}i,\:x=\frac{31}{12}-\frac{\sqrt{47}}{12}i\)

 Aug 12, 2021
 #1
avatar+502 
+2
Best Answer

Lets solvie this:

\(6x^2-31x+42=0\)

 

\(\frac{-\left(-31\right)\pm \sqrt{\left(-31\right)^2-4\cdot \:6\cdot \:42}}{2\cdot \:6}\)

 

\(\frac{-\left(-31\right)\pm \sqrt{47}i}{2\cdot \:6}\)

 

separate: \(x_1=\frac{-\left(-31\right)+\sqrt{47}i}{2\cdot \:6},\:x_2=\frac{-\left(-31\right)-\sqrt{47}i}{2\cdot \:6}\)

 

\(x=\frac{31}{12}+\frac{\sqrt{47}}{12}i,\:x=\frac{31}{12}-\frac{\sqrt{47}}{12}i\)

mworkhard222 Aug 12, 2021

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