Let Sn be the sum of the first n terms of the series 12 + 2.52 + 32 + 2.72 + 52 + 2.92 +... if S20 = 20A then A is equal to
a) 2001
b) 2019
c) 1851
d) 1951
e) None of these
Please provide an explanation as well.
Firstly, this is not really the sum of 1 sequence, it is the sum of 2 sequences
\(1^2+3^2+5^2+ .......\\ 2.5^2+2.7^2+2.9^2......\\ S_{20}=1^2+3^2+5^2+ .......+19^2\quad+ \quad 2.5^2+2.7^2+2.9^2......+4.3^2\)
I suppose I could just calculate the answer.
\(S_{20}=1330+118.9 = 1448.9\\ A=1448.9/20=72.445\)
Doesn't look like any of those answers to me.