algebra

Fill in the blank, so that that the resulting expression is the square of a binomial:
x^2 + 6/5*x +__

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$x^2+\frac{6}{5}x+$__

$a^2+2ab+b^2\\ a=x\\ 2ab=\frac{5}{6}x$

$2xb=\frac{6}{5}x\\ b=\frac{6\cdot x}{5\cdot 2\cdot x}\\ b=\frac{3}{5}$

$x^2+\frac{6}{5}x+(\frac{3}{5})^2=(x+\frac{3}{5})^2$

  !

Take 1/2  of the 'x' coefficient , square it and add it to the expression to 'complete the square

[(1/2)(6/5) ]² =   36/100      or   9/25     for the blank