+1694 The quadratic equation $x^2+4mx+m = 2x - 6$ has exactly one real root. Find the positive value of $m$.
+37069 ONE real root ( actually a double root) would mean the discrimination (from the Quadratic Formula) would be = 0
b^2 - 4ac = 0
X^2 + 4m x + m = 2x-6
x^2 - (4m - 2) x + (m+6) = 0 A = 1 B = 4m-2 C = m+6
(4m-2)^2 - 4 (1)(m+6) = 0
16 m^2 -16m +4 - 4m - 24 = 0
16 m^2 - 20m - 20 = 0 Now use quadratic formula To find M = 1.90587
