A bag contains 4 blue, 5 green and 3 red marbles. How many green marbles must be added to the bag so that at least 79 percent of the marbles are green?

Guest Jan 1, 2022

#1**+1 **

22 green marbles.

To solve, let x be the number of marbles added.

\(\frac{5+x}{12+x}>\frac{79}{100}\)

simplifying, we see that

\(x>21\frac{1}{3}\),

so x is at least 22.

If we put this back into the original problem, there would be 27 green marbles and 34 marbles total.

27/34 is about 0.79411, which is slightly above 79%.

OrcSlop Jan 2, 2022