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The roots of Ax^2+Bx+1 are the same as the roots of (x - 2)(x + 2). What is A+B?

 Jul 11, 2024
 #1
avatar+1897 
+1

First, let's focus on the expression we need A and B to be equal to. 

In order to find what we need, we need to be able to compare coefficients. let's convert it to standard form. 

We have

\((x - 2)(x + 2)=x^2-4\)

 

However, the constans don't match. Thus, we need to divide what we have by -4 to get a constant of +1. 

We have

\(-\frac{1}{4}x^2+1\)

 

Now. we cam compare coefficients. Since A is the coefficient of x^2, we have

\(A=\frac{-1}{4}\)

 

Since B is the coefficient of x, we have \(B=0\)

Thus, we finally have \(A+B=-\frac{1}{4}+0 = -\frac{1}{4}\)

 

So -1/4 is our final answer. 

 

Thanks! :)

 Jul 11, 2024

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