Algebra

We don't have the expand everything, as we can just use factoring to our advantage. 

Moving all terms to the right side of the equation, we get

$(x - 2)(x + 6) - (x - 2)(x + 5) \leq 0$

Now, since both terms have x- 2, we can factor it out to get

$(x-2)(x+6 - (x+5)) \le 0\\ (x-2)(x+6-x-5) \leq 0 \\ x-2 \leq 0$

Isolating x from the equation, we get

$x \le 2$

In interval notation, this is $(-\infty, 2]$

Thanks! :)