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The admission ticket to a baseball game is $\$5$ for children and $\$9$ for adults. On a certain night, 900 people were present at the baseball game and $\$6,500$ was collected. How many people attended the baseball game?

 

Part A.) Write a system of equations to represent this situation.

Part B.) Solve the system algebraically to find out how many children attended the baseball game.

 Feb 19, 2021
 #1
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We can write this as a system of equations. Let c be the number of children and a be the number of adults who attended.

 

900 people were present at the game ==> a + c = 900      .  (1)

 

$6500 was collected ==> 9a + 5c = 6500        . (2)

 

We can use the elimination method to find a and c. Multiply equation (1) by 5:

 

5a + 5c = 4500

9a + 5c = 6500

 

Subtracting both equations yields -4a = -2000, so a = 500 and c = 400.

 

Apologies for the formatting, I am new to the site.

 Feb 19, 2021

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