Algebra

$9^{x}-2\cdot 3^{x}+1$:

 

Set a = $3^x$

 

$a^2-2a+1=0$

$(a-1)^2=0$

a=1, so $3^x$=1

 

That means x=0 because anything to the 0th power is one

 

Hope this helps! 

 

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