+2668 We can rewrite the equation as: \(x^2-2x+9=0\)
Using Vieta's, the sum of the roots (a+b) is \(\large{-{b \over a}} = 2\), and the sum of the roots (ab) is \(\large {c \over a} = 9\)
We can also rewrite \(ab + a+b\) as \(ab + (a+b)\).
Can you take it from here?
