+121 Here is my attempt.
To simplify the expression 1√2+√3+1√2−√3, we need to rationalize the denominators of the fractions.
Let's start by rationalizing the first fraction: 1√2+√3⋅√2−√3√2−√3=√2−√32−3=−(√2−√3)=−√2+√3
Next, rationalize the second fraction: 1√2−√3⋅√2+√3√2+√3=√2+√32−3=−(√2+√3)=−√2−√3
Now, add the two rationalized fractions together:−√2+√3+(−√2−√3)=−√2+√3−√2−√3=−2√2
Therefore, the simplified expression is −2√2.
