+2668 We can rewrite \((a-4)+(b-4)\) as \(a+b-8\)
Using Vieta's formula, the sum of the roots is \(\large { -b \over a}\). Substituting the values, we find that \(a+b= -{1 \over 7}\)
Substracting 8 from this will yield you the answer...
+2668 We can rewrite \((a-4)+(b-4)\) as \(a+b-8\)
Using Vieta's formula, the sum of the roots is \(\large { -b \over a}\). Substituting the values, we find that \(a+b= -{1 \over 7}\)
Substracting 8 from this will yield you the answer...
