Given (14x+22)/(2x+18)=3x+1, compute the sum of all the possible values of x.
Express your answer as a fraction.
+36915 (14x+22)/(2x+18)=3x+1 Multiply both sides of the equation by (2x+18)
14x +22 = (3x+1)(2x+18) expand and simplify to
6x^2+42x-4 = 0 Now use Quadratic Formula to find x values
a = 6 b = 42 c = -4 in the Quadratic Formula
\(x = {-42 \pm \sqrt{42^2-4(6)(-4)} \over 2(6)}\)
