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The function f(x) is defined for 1 \le x \le 5 as follows:

f(x) = 2x + 8 if 1 \le x \le 2

f(x) = 13 - 5x if 2 < x \le 3

f(x) = 20 - 14x if 3 < x \le 4

f(x) = 40 + 5x if 4 < x \le 5

 

Find all real numbers x such that f(x) = x.  If you find more than one answer, list them all, separated by commas.

 Jun 2, 2024
 #1
avatar+1950 
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We basically just have to go thorugh every function and find when f(x) = x. 

 

First, we have f(x) = 2x + 8. 

We basically have 2x+8=x. Solving for this, we get x=8. Unfortunately, that is not in the range 1x2, so that wouldn't work. 

 

Second, we have f(x) = 13 - 5x. 

We have 135x=x. Solving this, we get x=13/6. This is in the range 2<x3, so 13/6 is a valid solution

 

Third, we have f(x) = 20 - 14x. 

We have 2014x=x. Solving this, we get x=4/3. This is not in the range of 3<x4, so it is not a valid solution. 

 

Lastly, we have f(x) = 40 + 5x. 

We have 40+5x=x. Solving this, we get x=10. This is not in the range 4<x5, so it is not a valid solution. 

 

So finally, we have x=13/6

 

Thanks! :)

 Jun 2, 2024
edited by NotThatSmart  Jun 2, 2024

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