Find the ordered triple (p,q,r) that satisfies the following system:
p - 2q = 3
q - 2r = -2 + q
p + r = 9 + p
From the second equation, note that the q cancels out. Isolating r, we get
q−2r=−2+q−2r=−2+q−qr=−2/−2=1
However, now take a look at the third equation. The p also cancels out. Isolating r again, we get
p+r=9+pp=9+p−pp=9
Since there are two DIFFERENT values of r given in one solution, this question has no solutions.
NO SOLUTIONS!
Thanks! :)