Find the ordered triple (p,q,r) that satisfies the following system:
p - 2q = 3
q - 2r = -2 + q
p + r = 9 + p
From the second equation, note that the q cancels out. Isolating r, we get
\(q-2r=-2+q\\ -2r=-2+q-q\\ r=-2/-2 = 1\)
However, now take a look at the third equation. The p also cancels out. Isolating r again, we get
\(p+r=9+p\\ p=9+p-p\\ p = 9\)
Since there are two DIFFERENT values of r given in one solution, this question has no solutions.
NO SOLUTIONS!
Thanks! :)